For a Poission distribution with large \(n\), use \(Z=\frac{\bar{X}-\lambda}{\sqrt{\lambda/n}}\) (i.e. \(\lambda\) instead of \(S\)).

It is approximately normal. Use it to test \(H_{0}:\lambda=\lambda_{0}\)

For a Poission distribution with large \(n\), use \(Z=\frac{\bar{X}-\lambda}{\sqrt{\lambda/n}}\) (i.e. \(\lambda\) instead of \(S\)).

It is approximately normal. Use it to test \(H_{0}:\lambda=\lambda_{0}\)

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